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Probability question

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    Probability question

    Rereading my notes on probability (I must be bored) I came across the following question:

    One part of a quiz consists of 2 multiple-choice questions with the suggested answers
    1. True
    2. False
    3. Insufficient Data to answer question.

    A student randomly marks one of the 3 answers to each question.

    What is the probability of exactly one correct answer?


    Answers please with reasoning.
    Hard Brexit now!
    #prayfornodeal

    #2
    Originally posted by sasguru View Post
    Rereading my notes on probability (I must be bored)
    Why do the rest of us have to suffer?

    Comment


      #3
      Originally posted by oracleslave View Post
      Why do the rest of us have to suffer?
      Bit grumpy aren't we?
      Didn't you have the requisite 30 bob in the red light district yesterday, then?
      Hard Brexit now!
      #prayfornodeal

      Comment


        #4
        Originally posted by oracleslave View Post
        Why do the rest of us have to suffer?
        WHS

        Comment


          #5
          1 in 9, since there are 3*3=9 combinations of answers: TT,TF,TI, FT,FF,FI, IT,IF,II

          Comment


            #6
            Originally posted by TimberWolf View Post
            1 in 9, since there are 3*3=9 combinations of answers: TT,TF,TI, FT,FF,FI, IT,IF,II

            The actual answer is 4/9. But I can't work out why.
            Your sample space is of course correct.
            Hard Brexit now!
            #prayfornodeal

            Comment


              #7
              Originally posted by sasguru View Post
              Bit grumpy aren't we?
              Didn't you have the requisite 30 bob in the red light district yesterday, then?
              Indeed, spent it all on beer .

              There are 3 questions and the and the probability of success in each question is 0.3. So n = 3,p = 0.3.

              The probability of x successes in n questions is nCx px qn–x where p and q are the probabilities of success and failure respectively.

              Substitute n = 3, x = 1, p = 0.3 and q = 1 – p = 0.3 in the formula.
              = 3C1 · (0.3)1 · (0.3)3 – 1


              etc etc *


              * I have no idea what any of this means, it is a straight copy from google

              Comment


                #8
                Fridays are dull enough without this sh1te...

                Older and ...well, just older!!

                Comment


                  #9
                  Originally posted by oracleslave View Post
                  Indeed, spent it all on beer .

                  There are 3 questions and the and the probability of success in each question is 0.3. So n = 3,p = 0.3.

                  The probability of x successes in n questions is nCx px qn–x where p and q are the probabilities of success and failure respectively.

                  Substitute n = 3, x = 1, p = 0.3 and q = 1 – p = 0.3 in the formula.
                  = 3C1 · (0.3)1 · (0.3)3 – 1


                  etc etc *


                  * I have no idea what any of this means, it is a straight copy from google
                  Must have been good strong beer
                  Hard Brexit now!
                  #prayfornodeal

                  Comment


                    #10
                    Originally posted by sasguru View Post
                    Must have been good strong beer

                    Comment

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